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Maorey avatar Maorey commented on July 20, 2024 1

每次提交耗时不太一致,但也和你差不多

function fibonacci(n) {
  let a = 0, b = 1, c = 0
  if (--n > 1) {
    while (--n) {
      c = a + b
      a = b
      b = c
    }
  } else if (n > 0) {
    c = 1
  }
  return c
}

(标记为JavaScript在你的博客里看不到...)

from brush_algorithm.

 avatar commented on July 20, 2024
array.splice(2, 1); // 将数组恢复成 斐波纳契数列
// 应改为
array.splice(1, 1);
or
array.splice(0, 1);

你裁剪错地方了吧

from brush_algorithm.

jzyismylover avatar jzyismylover commented on July 20, 2024

其实直接用递归就好

function getFIBONumber(n) {
  if(n == 1) return 0;
  else if(n == 2) return 1;
  else return getFIBONumber(n-1) + getFIBONumber(n-2);
}

from brush_algorithm.

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