Comments (2)
Thanks Josip, but I am only anding the first byte, then appending the
second byte onto it after a shift of 8. So I am getting full 14bit
resolution.
output = ( (uint16_t)( read_val[0] & 0x1F ) << 8 ) + read_val[1];
On Tue, Jun 21, 2016 at 1:26 PM, Josip Basic [email protected]
wrote:
0x1F should be changed to 0x3F to correctly read 14-bit pressure that
HSC offers.Regards,
Josip—
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You're getting 13-bit resolution: max(read_val[0] & 0x1F) + max(read_val[1]) = 7936 + 255.
Since 0x1F = 0b11111, you're missing one bit. You need 6 bits from read_val[0], as the status takes 2 bits. Thus I believe 0x3F = 0b111111 is needed.
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