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ruochenjia avatar ruochenjia commented on May 3, 2024 1

@RyanCavanaugh Logically the method you suggested should behave exactly the same as the one I mentioned above. However when I tested with the code below, only the key and value part works correctly, the overlay does not. Invoking a function on the overlay produces an error message:

This expression is not callable. Type 'String' has no call signatures.

The code I used:

type SuperRecord<Key extends keyof any, Value, Overlay = {}> = {
	[E in Key]: E extends keyof Overlay ? Overlay[E]: Value;
};
interface K extends SuperRecord<string, string, { func1(): void; }> {
}
let k: K = ...
k["str"] = "val"; // works fine
k.func1(); // error
k.toString(); // works fine

from typescript.

RyanCavanaugh avatar RyanCavanaugh commented on May 3, 2024

This seems like just an exact duplicate of #17867.

You can already write

type SuperRecord<Key extends keyof any, Value, Overlay = {}> = {
    [E in Key]: E extends keyof Overlay ? Overlay[E]: Value;
};

to get the generic behavior on an index signature's output type, nothing new is needed.

from typescript.

RyanCavanaugh avatar RyanCavanaugh commented on May 3, 2024

Right, you'd still need rest signatures. But K would be declared as this:

type O = { func1(): void; };
interface K extends SuperRecord<keyof O, string, O> {
  // TODO: Be able to uncomment.
  // [...rest: string]: string
}

from typescript.

typescript-bot avatar typescript-bot commented on May 3, 2024

This issue has been marked as "Duplicate" and has seen no recent activity. It has been automatically closed for house-keeping purposes.

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