Recognize hierarchical URIs with authority about uri HOT 2 CLOSED

Curious! Indeed, the .resolve() method isn't applying those fragments properly.

>>> a = uri.URI("ldap://[2001:db8::7]/c=GB?objectClass?one"); a
URI('ldap://[2001:db8::7]/c=GB?objectClass?one')
>>> a / "/c=NO"
URI('ldap://[2001:db8::7]/c=NO')

While the "resolve" method does not correctly handle this case, the division operator does. It ought to correctly resolve this, however. Thanks for reporting! The second case isn't quite as simple.

>>> a = URI('sftp:example.com/etc/passwd'); a
URI('sftp:example.com/etc/passwd')  # looks right, but this is an illusion
>>> a.authority  # no host component
''

In this particular case, : is insufficient. The sftp scheme defines the following syntax:

sftp://[<user>[;fingerprint=<host-key fingerprint>]@]<host>[:<port>]/<path>/<file>

While adding the // does allow it to parse correctly, the REPR is not an identity transform. (This is also an issue.)

>>> a = URI('sftp://example.com/etc/passwd'); a
URI('sftp:example.com/etc/passwd')
>>> a.authority
'example.com'

I'll need to add sftp as a recognized URL-like protocol via https://github.com/marrow/uri/blob/develop/setup.py#L98

The last case is explained by non-URL URI treating everything after the authority part as path. For most URI schemes (e.g. URN, ISBN, etc., etc.) the part after the protocol is protocol-defined and arbitrary.

from uri.

Adding the registration of sftp = uri.scheme:URLScheme to setup.py and issuing a setup.py develop call to link it, SFTP URI now behave correctly:

>>> a = uri.URI("sftp://example.com/etc/passwd"); a
URI('sftp://example.com/etc/passwd')
>>> a.resolve("/root")
URI('sftp://example.com/root')
>>> uri.URI("sftp:example.com/etc/passwd")
URI('sftp://example.com/etc/passwd')

This'll be bundled in the next release, this week. Available in commit a8718ac. (If you are impatient, you can link this entry_point in your own application; just remember to remove your own registration of it after you update your URI version.)

from uri.