Comments (3)
Cool! Just to clarify: the modified version will work in IPython but not in the standard Python console: i.e. the %gui
will cause an error. You could either make separate examples or use something like this to make it work in both environments:
is_ipython = False
try:
if 'terminal' in str(type(get_ipython())):
is_ipython = True
except:
pass
if is_ipython:
# Initialize GUI event loop
%gui qt5
# Tell vtkplotter not to embed the Window
from vtkplotter import embedWindow
embedWindow(False)
from PyQt5 import Qt
from vtk.qt.QVTKRenderWindowInteractor import QVTKRenderWindowInteractor
from vtkplotter import Plotter, Cone
class MainWindow(Qt.QMainWindow):
def __init__(self, parent=None):
Qt.QMainWindow.__init__(self, parent)
self.frame = Qt.QFrame()
self.vl = Qt.QVBoxLayout()
self.vtkWidget = QVTKRenderWindowInteractor(self.frame)
self.vl.addWidget(self.vtkWidget)
vp = Plotter(qtWidget=self.vtkWidget, axes=4, bg='white')
vp += Cone()
vp.show() # create renderer and add the actors
# set-up the rest of the Qt window
self.frame.setLayout(self.vl)
self.setCentralWidget(self.frame)
self.show() # <--- show the Qt Window
if not is_ipython:
app = Qt.QApplication([])
window = MainWindow()
from vedo.
thanks, indeed my idea was to make 2 separate examples!
M
from vedo.
Thanks a lot Philipp for fixing this! I'll modify the example in the next release.
M
from vedo.
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from vedo.