How can i obtain ip.src in human readable form? about dpkt HOT 7 CLOSED

there's a dpkt.hexdump() that is pretty good in that it will basically show you 
a
sniffer view.  Otherwise it helps to open the packet in a sniffer like
wireshark/tcpdump/snoop/old ethereal that can decode the packet for you  and 
tell you
what each byte means (cause that's what you're dealing with sometimes).  Or 
I've seen
some other code that makes its own pcap handler that does something with
packets...maybe try that? Also it appears that the dpkt lib uses .unpack() to 
parse
packets out.  Try data = IP.unpack(), get data into UDP(), then UDP.unpack()? 

i still cant access to IP source address, can you show me  a little code 
snippet?

all source w/o comments-damn

Dodin,

You can simply use socket's ntoa function:

print socket.inet_ntoa(ip.src)

Or if you're already using dnet as well:

print dnet.ip_ntoa(ip.src)

Regards,
Jon Oberheide

ok, thanx

ok, thanx

Dodin,

I like being able to read the IP addresses in human readable form too.
fHere is a patch to ip.py to print the "src" and "dst" fields in human 
readable form.  Nom if you have a packet instance you can just do
repr(packet) to display the packet with human readable ip src/dst fields.

Have a nice day, 

# Aaron

use socket inetb notation
src=socket.inet_nota(ip.src)
 thats all

u ll get a ans