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ch-yx avatar ch-yx commented on September 7, 2024
>>> a=[1,2]
>>> g=(i for i in a)
>>> list(g)
[1, 2]
>>> list(g)
[]
>>> 

因为你在list(g)的时候把g消耗了

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ch-yx avatar ch-yx commented on September 7, 2024

和执行时机差异没关系。
这个g就是只能用一次。
即使是(i for i in a)这样什么运算也没有也是如此

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leisurelicht avatar leisurelicht commented on September 7, 2024

python中这种小括号括起来的情况叫生成器表达式,返回的是一个生成器。而python中的生成器只能迭代一次。list操作会进行一次迭代导致生成器被使用。

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