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lava avatar lava commented on July 27, 2024

Should be possible, either by passing a "format" keyword like o (note the leading space) to plot(), or by exposing the scatter function yourself and then making a pull request ;)

from matplotlib-cpp.

Apollys avatar Apollys commented on July 27, 2024

Okay, that works very well. For anyone else needing this, simply do:

matplotlibcpp::plot(x, y, "o ");

from matplotlib-cpp.

Apollys avatar Apollys commented on July 27, 2024

Full working example:

#include <vector>

#include <matplotlibcpp/matplotlibcpp.h>

int main() {
  const int kNumData = 10;
  std::vector<int> x(kNumData);
  std::vector<int> y(kNumData);
  for (int i = 0; i < kNumData; ++i) {
    x[i] = i;
    y[i] = kNumData - i;
  }
    
  matplotlibcpp::plot(x, y, "o ");
  matplotlibcpp::show();
  
  return 0;
}

More detailed info about flags to pass to fmt argument here (see Notes section).

from matplotlib-cpp.

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