An additional option of plot.AccurateGLM about aglm HOT 4 CLOSED

Can you explain which kind of plots are expected　and how it works when s is not given?

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Can you explain which kind of plots are expected

When lambda is a single value, plot(aglm(x, y, lambda = lambda, ...)) (without s =) is already available.
So, I can say, plot(aglm(x, y, lambda = lambda.list, ...), s = lambda) should produce roughly the same plots as plot(aglm(x, y, lambda = lambda, ...)) does, where lambda.list is a vector an element of which is lambda.
Only the differences between the two sets of plots are tiny computational differences.

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@iwahiropuzzles Thank you for your clarification, and I realized that there is no need to plot for multiple lambda values in one plot.AccurateGLM call? In other words, your intention is to plot coefficients corresponding to one lambda value, with one aglm object trained with multiple lambda values?

If my understanding is true, the implementation will be straightforward and nothing is cost.

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Yes, you seem to understand what I mean. Thanks.

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