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Lee-Janggun avatar Lee-Janggun commented on August 28, 2024

What the slide is saying that without protection, the access may be unsafe.

Now even if you did protection, the pointer may have been freed between the time you obtained it and called protect(cur). We perform validation to ensure that this does not happen.

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leporia avatar leporia commented on August 28, 2024

Hence we can call protect on an already freed pointer safely? I.e. the protect method doesn't dereference the pointer
Is this: protect(null) also safe then?

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Lee-Janggun avatar Lee-Janggun commented on August 28, 2024

protect(null) itself is safe (hence in the homework Shield::protect() is a safe function) what isn't safe is dereference of a null pointer or protected pointer without validation. This is precisely why we validate the pointer and also check if its null.

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BraSDon avatar BraSDon commented on August 28, 2024

Okay, so protecting a pointer to invalid memory is safe. Then why does it say "unsafe protect()" on slide 7?

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Lee-Janggun avatar Lee-Janggun commented on August 28, 2024

Ah, so the situation in slide 7 is a case where the dereference is unsafe even if validation succeeds. That's why its saying "unsafe protect()".

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