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yixianluo avatar yixianluo commented on June 2, 2024

碰到类似问题，sm4是按16的倍数进行加密，有其他js实现跨越参考吗

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mu-yu avatar mu-yu commented on June 2, 2024

@yixianluo 原始字符串可以是任意长度的，只不过要进行 padding/unpadding，这个库没有实现这一步而已。

还有这个可以参考下：
sm-series-crypto

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fancyboynet avatar fancyboynet commented on June 2, 2024

不知道作者有没有计划修复这个问题

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gy0801151351 avatar gy0801151351 commented on June 2, 2024

SM4对于key和iv的要求都是128位, 但是找了好多前端js的算法, 都把128位理解错了( 单纯的把128位换算成字符串的长度限制为16了, 其实是需要按字节位数换算. 比如base64格式和hex格式的key和iv, 需要先转换格式). 导致前端的sm4加密无法使用后端语言解密.

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mu-yu avatar mu-yu commented on June 2, 2024

SM4对于key和iv的要求都是128位, 但是找了好多前端js的算法, 都把128位理解错了( 单纯的把128位换算成字符串的长度限制为16了, 其实是需要按字节位数换算. 比如base64格式和hex格式的key和iv, 需要先转换格式). 导致前端的sm4加密无法使用后端语言解密.

无法解密可能是加密模式不同导致的，同样的 sm4,还分 cbc 和 ecb 等…

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JuneAndGreen avatar JuneAndGreen commented on June 2, 2024

key 要求 128 比特，加解密字符串在 0.2.0 版本支持了字符串输入和填充，详情可参考 README 或 testcase。

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