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DaveBoy avatar DaveBoy commented on May 17, 2024

首先，volatile确实不具有原子性，但是对于long和double的读取好像是有原子性的（不用volatile修饰不具有原子性）。
其次“• 原子性：对任意单个 volatile 变量的读 / 写具有原子性，但类似于 volatile++ 这种复合操作不具有原子性。”这句话的正确理解是“任意变量（应该是要排除long和double，但是加了volatile就不用排除了）的读 / 写具有原子性，但i++ 是个复合操作，不具有原子性。”

from tobetopjavaer.

zengxiangjiang avatar zengxiangjiang commented on May 17, 2024

您好，非常感谢您的解惑。

from tobetopjavaer.

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