Adding/modifying query parameters inline about furl HOT 4 CLOSED

To set individual query string parameters, as in your example, use the args or query_params parameter of add().

>>> from furl import furl
>>> f = furl('http://www.a.de/?a=b')
>>> f.add(args={'x':'z'})
>>> f.url
'http://www.a.de/?a=b&x=z'

args is also the first parameter of add(), and thus can be optionally omitted.

>>> f = furl('http://www.a.de/?a=b')
>>> f.add({'x':'z'})
>>> f.url
'http://www.a.de/?a=b&x=z'

Or, all in one line

>>> furl('http://www.a.de/?a=b').add({'x':'z'}).url
'http://www.a.de/?a=b&x=z'

Does that answer your question?

from furl.

I see I didn't specify the problem well enough, sorry! I'm looking for a way to replace parameters that might or might not be already present in the query string. Here's a better example:

>>> furl('http://www.a.de/?page=1').add({'page': '2'}).url
'http://www.a.de/?page=1&page=2
# I actually would like to get 'http://www.a.de/?page=2'

I could use set(), but that removes any other unrelated parameters that are in the query string:

>>> furl('http://www.a.de/?search=foo&page=1').set({'page': '2'}).url
'http://www.a.de/?page=2
# I actually would like to get 'http://www.a.de/?search=foo&page=2'

from furl.

The set() method of furl objects sets entire URL components, like the query, in the absolute sense. That is, set() replaces existing URL components with those provided.

To set individual query parameters with a dictionary-like object, call set() on the Query object instead of the parent furl object.

>>> f = furl('http://www.a.de/?search=foo&page=1')
>>> f.query.set({'page': 2})
>>> f.url
'http://www.a.de/?search=foo&page=2'

To accomplish the aforementioned in one line, combine remove() and add().

>>> from furl import furl
>>> furl('http://www.a.de/?search=foo&page=1').remove(['page']).add({'page': 2}).url
'http://www.a.de/?search=foo&page=2'

Do either of the above satisfy your needs?

from furl.

Yes, thank you :-)

from furl.