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boggddan avatar boggddan commented on May 28, 2024 1

вот еще один вариант решения

type TrimLeft<S extends string> = S extends ` ${infer T}` | `${infer T} ` ? TrimLeft<T> : S;
type trimed = TrimLeft<'  Hello World  '> // expected to be 'Hello World  '
type trimed2 = TrimLeft<'  Hello World'> // expected to be 'Hello World  '
type trimed3 = TrimLeft<'Hello World  '> // expected to be 'Hello World  '

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bini1988 avatar bini1988 commented on May 28, 2024 1

Решение через union:

type TrimChars = ' ' | '\n' | '\t';
type Trim<S extends string> = S extends `${TrimChars}${infer R}` | `${infer R}${TrimChars}` ? Trim<R> : S;

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ghaiklor avatar ghaiklor commented on May 28, 2024

@boggddan этот даже попроще будет, хороший трюк с объединением 👍🏻

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