Comments (8)
Does chaining the class work ?
.class1.class2 ?
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Yikes, that's obvious isn't it (I meant to concatenate instead of cascade). I will try tomorrow and report. In any case I will still have some questions (e.g., why can't a class be used in a filter). Thanks.
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Yes, concatenation works findFirst(".class1.class2"). Also, I discovered that classes can be retrieved with element.getAttribute("class").
Following that convention, I have understood that filtering on classes can be achieved with the attribute filter: with("class").
Deprecated way:
browser.findFirst("#top-menu", with("class", contains("nav")));
Current way:
browser.findFirst("#top-menu", with("class").contains("nav"));
Except, this isn't quite right either, because contains is just a substring search. You really need:
browser.findFirst("#top-menu", with("class").contains(regex("\\bnav\\b")));
Would be really convenient to have this in a withClass filter.
thanks!
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Why not just use with("class").equalTo("nav")); ?
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I believe when there is more than one class this will not work.
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We now have browser.findFirst("#top-menu", withClass().containsWord("nav")));
For multiple classes, browser.findFirst("#top-menu", withClass().containsWord("nav"),withClass().containsWord("nav2")));
We keep looking of a more "fluent" syntax but does that sounds good for your need ?
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Thanks so much for adding withClass and containsWord. This is much better than before, and I would think a lot of people would use it.
For future readers, this was added in: 5a22ae7
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It's now available on 0.7.9
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