Using results outside of the async about feel HOT 1 CLOSED

I believe you may have figured it out yourself by now.
The Promise.then is called asynchronously and your console.log(x) is executed beforehand.

Either use the result inside the then callback

 x = promise.then(
    result =>{
         console.log(result); 
         return (result);
   } 
);

OR use async await syntax

 x = await promise;
console.log (x);

from feel.