Comments (2)
@B-one
你知道为什么下面这个函数中需要进行转置吗?
def generateBoundingBox(map, reg, scale, t):
stride = 2
cellsize = 12
'''为什么需要转置 ?? '''
map = map.T
dx1 = reg[0,:,:].T
dy1 = reg[1,:,:].T
dx2 = reg[2,:,:].T
dy2 = reg[3,:,:].T
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@B-one 我知道为什么要转置了,就是因为之前reshape(channels,w,h),所以画图的时候要转置过来;但是我尝试着直接reshape(channels,h,w)将图片送进网络的话,虽然还能够识别,但对于某些图片,准确率没有reshape(channels,w,h)高,你知道原因吗
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Related Issues (20)
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