Comments (3)
Does T.prototype.length
actually make sense? T.foo
is a namespace dereference, so I don't think there's any sense of prototype chain.
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In type position, T::length
currently compiles to T["length"]
.
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Oops, right, I see.
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Related Issues (20)
- Cannot use `@#` for `this.length` in `while` condition HOT 1
- Unbounded for loop
- Arrow functions after binary operators don't parse right HOT 1
- Ref hoisting in `async do` HOT 1
- `if const` allows `?` in identifier
- Empty spread invents identifier
- try...else HOT 11
- ts-expect-error before assignment from for expression HOT 4
- `[a, ..., b] = c` doesn't declare `ref`
- Pattern matching in condition with literals generates incorrect code
- Optional-chained operators HOT 2
- "try coalescing" / catch operator
- Type specification in `for`
- Negative index access fails on its own line
- Deep `....`rest operator HOT 2
- Eliminating `return` after `loop` in some cases HOT 3
- `yield x; loop` has strange behavior
- Trailing pipe or property access should expressionize statement HOT 1
- ASI fails before symbol-typed property
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