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Comments (6)

alfredh avatar alfredh commented on August 12, 2024

testing values and execution time:

0E99999999     0.2 seconds
0E999999999    2.3 seconds
0E9999999999   23 seconds
0E99999999999  4m3.176s

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alfredh avatar alfredh commented on August 12, 2024

the following solution was suggested by Chris Owen:
(in src/json/decode.c)

static inline double mypower10(uint64_t e)
{
	double n, p;

	n = 1.0;
	p = 10.0;
	while (e > 0) {
		if (e & 1) {
			n *= p;
		}
		p *= p;
		e >>= 1;
	}
	return n;
}

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alfredh avatar alfredh commented on August 12, 2024

I have tested with a couple of different solutions, and measured the performance.
The input JSON contains some numbers with exponent, and the decoding is
repeated 10000 times.

  1. use pow from libm: 160049 usec
    (a disadvantage here is adding a dep to libm)

  2. use patch from Chris: 160883 usec

  3. in is_number use strtol instead: 305448 usec

The slowest solution is number 3 (use strol).

Solution number 1 and 2 has almost the same performance.

@richaas if you agree, I can prepare a PR for solution number 2.

here is the test JSON file:

{
  "array" : [
    0e9,
    0e99,
    0e999,
    0e9999,
    0e99999,
    0e999999,
    0e9999999,
    0e99999999,
    0e999999999,
    0e9999999999,

    1e9,
    1e99,
    1e999,
    1e9999,
    1e99999,
    1e999999,
    1e9999999,
    1e99999999,
    1e999999999,
    1e9999999999,

    2e10,
    2e100,
    2e1000,
    2e10000,
    2e100000,
    2e1000000,
    2e10000000,
    2e100000000,
    2e1000000000,
    2e10000000000,

  ]
}

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richaas avatar richaas commented on August 12, 2024

Yes, let's go for alternative 2. How will we handle resulting numbers to large to fit in long double?

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alfredh avatar alfredh commented on August 12, 2024

here is the PR: #88

currently there is no checks in the code for boundaries/overflow.
both the base number and the exponent number is built up by parsing in reverse
the string containing [0-9].

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richaas avatar richaas commented on August 12, 2024

Issue resolved in PR #88

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