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hucheng avatar hucheng commented on August 10, 2024

Note that the aggregating (sum) of two HashVectors cost more than sum of two sparseVector. So the key is to avoid the new operation but with in-place add. Please be referred to aggregateByKey.

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bhoppi avatar bhoppi commented on August 10, 2024

I tried several open address Hashmap implementations used as HashVector backend, but surprisingly they are all slower than SparseVector (Java's HashMap >> Spark's OpenHashMap > Breeze's OpenAddressHashArray > fastutil's int-int map). Maybe because the conflicts happen at the average of log(K) times.
But now this issue is perfectly solved using a very easy trick: before we sample all the edges of one term, we transform the term's count vector into DenseVector first. Then finding n_kw will just need O(1).

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