【每日一题】– 2019-10-12 - IP地址存储 about fe-interview HOT 1 CLOSED

function IP2Int(str) {
  // "192.168.0.1"
  let n = BigInt(0);
  // a << 1
  // a << 2
  str
    .split('.')
    .reverse()
    .forEach((c, i) => {
      n += BigInt(+c) << BigInt(8 * i);
    });

  return n; // 2^31 - 1
}

IP2Int("192.168.0.1")