[feature request]: Get contributors data from Github API about eazyloader HOT 29 CLOSED

You can create one for yourself and try with that.
Make sure, you don't commit that. You can put that in the .env file
For the project deployment, I'll use mine

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Oops, forgot that.
In that case, you can return something like :

contributors = [
    {
        "name": "Contributor 1",
        "username": "contri1",
        "profile_url": "https://github.com/contri1/"
    },
    {
        "name": "Contributor 2",
        "username": "contri2",
        "profile_url": "https://github.com/contri2/"
    }
]
return contributors

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Nope, I don't think so as the user need not perform any extra step for getting added as contributors

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There were some minor bugs in the workflows.
Need not worry about them

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Thanks for contributing @Tawishi
Feel free to add more features, and create issues

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hey @ashutoshkrris. I would like to work on this issue

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Sure @Tawishi , go ahead!

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I am able to fetch the contributors, excluding the bot, using the Github API
where do we want these to be added in the backend?

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you can create a file called contributors.py within the core package @Tawishi
also, if possible use Github access tokens to increase the number of requests

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ok @ashutoshkrris

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@ashutoshkrris what data is needed out of this?

"author": {
            "login": "ashutoshkrris",
            "id": 47353498,
            "node_id": "MDQ6VXNlcjQ3MzUzNDk4",
            "avatar_url": "https://avatars.githubusercontent.com/u/47353498?v=4",
            "gravatar_id": "",
            "url": "https://api.github.com/users/ashutoshkrris",
            "html_url": "https://github.com/ashutoshkrris",
            "followers_url": "https://api.github.com/users/ashutoshkrris/followers",
            "following_url": "https://api.github.com/users/ashutoshkrris/following{/other_user}",
            "gists_url": "https://api.github.com/users/ashutoshkrris/gists{/gist_id}",
            "starred_url": "https://api.github.com/users/ashutoshkrris/starred{/owner}{/repo}",
            "subscriptions_url": "https://api.github.com/users/ashutoshkrris/subscriptions",
            "organizations_url": "https://api.github.com/users/ashutoshkrris/orgs",
            "repos_url": "https://api.github.com/users/ashutoshkrris/repos",
            "events_url": "https://api.github.com/users/ashutoshkrris/events{/privacy}",
            "received_events_url": "https://api.github.com/users/ashutoshkrris/received_events",
            "type": "User",
            "site_admin": false
        }

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From this API, the avatar_url and html_url would be fine. Also, there is some other API to fetch user details such as it's name. Can we use that to get the contributor's name? @Tawishi

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ok, so getting the avatar_url and html_url is done
looking for a way to get the contributor's name

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This API might be useful : https://api.github.com/users/{username}

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this works @ashutoshkrris
we have the avatar_url html_url and name now
so contributors.py has 2 functions -

• for getting contributors avatar_url, html_url, github username
• for getting name of contributor using github username

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We're making use of GITHUB API TOKENS in the headers, right?

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almost forgot that. working on it

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Hey @Tawishi
Head over to #13 and let's discuss this

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i got the answer in the docs that is why I removed the comment @ashutoshkrris
Thank you for the update, anyways

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we will use whose personal token here?

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what should the data be returned as, any specific return type of the required contributor information like JSON, etc.?

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you can just return a python dictionary from your function or method.

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ok

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you can return like this :

result = {
    "username": username,
    "name": name,
    "profile_url": html_url
}
return result

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we have a list of contributors, so a list of such dictionaries? or how do you suggest I represent multiple contributors?

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all done. I will create a PR
Please ping here in case changes are needed.

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does this need any documentation update?

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@ashutoshkrris checks are failing. Could you please check if any changes are needed from my end?

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Thank you @ashutoshkrris for your sypport and patience

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